Question 1 - Answer

1a) To answer this question we will consider the two columns MAJ and POL. This is k-sample data: Think of the data rearranged in a table with the POL measurements for students with MAJ=1 (psych) in the first column, MAJ=2 (bio) in the second column etc.

b) From Minitab we obtain the following values for mean and standard errors of the mean.

               MAJ        N     MEAN   SEMEAN
 POL             1       18    3.361   0.249
                 3       22    3.091   0.215
                 4       23    3.439   0.222
                 5        5    3.400   0.245
                11       36    3.028   0.152


3.5  |                             +
     |     
3.4  |                                         +
     |     +
3.3  |
     |
3.2  |
     |
3.1  |
     |                 +
3.0  |                                                     +
     +-----+-----------+-----------+-----------+-----------+---
       psych          bio         pps         soc         other

c) The average response in the 5 groups seem very similar. the small differences can be attributed to chance. The sample means are so close that it is impossible to tell whether differences reflect true effects, or are just due to random errors.