(a) 32, 66, 78.5, 84.5, 98
Problem 3.
The histogram is skewed to the left due to the outlier. Ignoring the outlier it is fairly evenly spread out over the range 55 to 98 with some clumping in the middle.
Problem 5.
Any set where all five numbers are equal.
Problem 8.
Mean = 25, variance = 125, so standard deviation = 11.18
Problem 10.
(b) Hours of sleep for males and females are similar except that there are a few males who are outliers because they slept so many hours.
Problem 11.
(b) The histogram is probably more useful since it provides all of the information provided by the boxplot, plus more information on the shape.
Problem 12.
(a) Mean would be higher.
(b) Median would be higher. There would be some very young ages pulling the mean down. In other words, the picture would be skewed to the left.
(c) Mean would be higher. There would likely be a few expensive ones, pulling the mean up.
(d) The mean and the median would be about the same because the heights are likely to be approximately bell-shaped.
(e) The mean and median should be about the same, because shoe sizes are not likely to have more extreme outliers in one direction than the other.
Problem 22.
The standard deviation is 16, so the variance is 256.